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Showing posts with label chemistry. Show all posts
Showing posts with label chemistry. Show all posts

Saturday, May 28, 2011

Chemical Bonding (Section 1 of 2)

Contents of this Page:
  1. The Bond Energy
  2. Factors affecting the Bond energy
  3. The Four Main Types of Bonding
    1. Ionic Bonding
    2. Covalent Bonding
    3. Dative Covalent Bonding
    4. Metallic Bonding
  4. Section 2
============================================
    The Bond Energy
    The energy required to break one mole of covalent bonds in gaseous state is called bond energy
    For Example
    H=H Bond Energy = +436 KJ/mol
    I-I Bond Energy = +151 KJ/mol


    Factors affecting Bond Energy
    • Number of Bonds: Triple bonds are stronger than double bonds and double bonds are stronger than single bonds.
    • Bond Length: Bond length is the distance between two nuclei of covalently bonded atoms as the bond length increases bond strength decreases, hence bond energy decreases
    Ionic
    •  between atoms on Left Hand Side and atoms on Right Hand Side of Periodic Table
    •  electrons are TRANSFERRED between atoms
    •  atoms end up as ions
    •  strong electrostatic attraction between ions of opposite charge
    •  giant ionic crystal lattice structure
    •  Properties ... high melting points.....brittle.....water soluble....conduct when molten or in aqueous solution

     
    Ionic Bonding; a video demonstration:
    Drawing dot and cross diagrams

    http://www.youtube.com/watch?v=8BZBzFwVXl4


    Covalent Bonding
    •  between atoms of the same element;   (e.g. in N2, O2, diamond, graphite)
    •  between atoms of different elements on the RHS of table; (e.g. CO2,  SO2)
    •  when one of the elements is in the middle of the table;  (e.g. C, Si)
    •  head-of-the-group elements with high I.E.’s , (e.g. Be in BeCl2)
    •  consists of a shared pair of electrons, one electron coming from each atom
    •  atoms share to try and get an ‘octet’ of electrons
    •  leads to the formation of simple molecules and giant molecules (e.g. silica)


    Polar Covalent Bonds
    In bonds between atoms of the same element the sharing of the electrons is equal between the two atoms. When two atoms of different elements make a bond, the electrons will not usually be shared equally. The electrons are pulled more toward the more electronegative element.

    What is electronegativity?
    Electronegativity is the measure of the ability of an atom in a molecule to draw bonding electrons to itself. In general, electronegativity increases from bottom to top and left to right on the periodic table. Fluorine is the most electronegative element since it has a tendency to pick up electrons easily and hold on to them strongly. An element like cesium has a low electronegativity. The unequal sharing of electrons is called a polar covalent bond. The definition of a polar covalent bond is a covalent bond in which the bonding electrons spend more time near one atom than the other.

     

    Dative Covalent Bonding
    •  consists of a shared pair of electrons, both electrons from one atom
    •  one species is a lone pair donor - LEWIS BASE
    •  other species has space in outer shell to accept a lone pair - LEWIS ACID
    •  once the bond has been formed it is the same as a covalent bond

    Metallic Bonding
    •  metal atoms arranged in regular lattice give up outer shell electrons
    •  electrons form a mobile ‘cloud’ which binds metal ions together
    •  strength of bond depends on number of electrons and size of ions
    •  mobile electrons ... allow electricity to be conducted

    Strength of a Metallic Bond:
    As we go down the group the atomic size increases, the attraction between the nucleus and free electrons decreases and therefore the melting melting point also decreases down the group.
    As we move across the period, atomic size decreases and the strength of the metallic bond increases therefore melting point also increases
    Sources:
    Images and definitions: www.knockhardy.org.uk
    Videos: Youtube.com

    The VSEPR theory 
    VSEPR theory proposes that the geometric arrangement of terminal atoms, or groups of atoms about a central atom in a covalent compound, or charged ion, is determined solely by the repulsions between electron pairs present in the valence shell of the central atom. To view more about VSEPR theory visit this page
    The Sigma and Pie bonds


    Friday, May 27, 2011

    Atoms molecules and stoichiometry

    Before proceeding with this section please make sure you have seen all the lectures on the Basic Calculations in A-level Chemistry page

    Mass number and atomic number

    Atomic Number (Z)      Number of protonsin the nucleus of an atom
    Mass Number (A)       Sum of the protons and neutronsin the nucleus

    What is the avogadro's constant?
    The Avogadro Constant is a constant number used to refer to atoms, molecules, ions and electrons. Its value is 6.023 x 1023 mol-1 . I.E 1 Mole of Sodium contains  6.023 x 1023 number of particles.

    What is the Relative Atomic Mass (Ar)?


    The mass of an atom relative to the 12C isotope having a value of 12.000 is called as the Ar.

    Relative Isotopic Mass Similar, but uses the mass of an isotope Eg 238U
    Relative Molecular Mass (Mr) Similar, but uses the mass of a molecule Eg CO2,  N2
    Relative Formula Mass Used for any formula of a species or ion E.g NaCl,  OH¯




    What are Isotopes?Definition Atoms with ...  the  same atomic number but different mass number                                                                                                              or
                             the  same number of protons but different numbers of neutrons.

    Important: Chemical properties of isotopes are identical 

    Example: Chlorine contains 75% by mass Cl (35) and 25% by mass Cl (37). Calculate the relative atomic mass of Chlorine.

    Ar of Cl = (75 x 35) + (25 x 37)  = 35.5
                                  100

    What is the mass spectra?

    A mass spectrum is an intensity(Abundance) vs. m/z (mass-to-charge ratio) plot representing a chemical analysis. Hence, the mass spectrum of a sample is a pattern representing the distribution of ions by mass (more correctly: mass-to-charge ratio) in a sample.










    How to calculate the Relative Atomic mass from a mass spectra












    What is the empirical formula

    A formula that gives the simplest whole-number ratio of atoms in a compound.

    How to calculate the empirical formula?
    1. Start with the number of grams of each element, given in the problem. 
      • If percentages are given, assume that the total mass is 100 grams so that 
      • the mass of each element = the percent given.
    2. Convert the mass of each element to moles using the molar mass from the periodic table. 
    3. Divide each mole value by the smallest number of moles calculated. 
    4. Round to the nearest whole number.  This is the mole ratio of the elements and is 
    5. represented by subscripts in the empirical formula. 
      • If the number is too far to round (x.1 ~ x.9), then multiply each solution by the same 
      • factor to get the lowest whole number multiple. 
        • e.g.  If one solution is 1.5, then multiply each solution in the problem by 2 to get 3. 
        • e.g.  If one solution is 1.25, then multiply each solution in the problem by 4 to get 5.
    Example;
    A compound was found to contain 13.5 g Ca, 10.8 g O, and 0.675 g H.  What is the empirical formula of the compound?
    Calculating empirical formula from combustion data
    Example : Calculating the empirical formula of a hydrocarbon

    The general procedure:
    • Calculate the number of grams of carbon in the compound by calculating the number of grams of carbon in the given amount of CO2.
    • Calculate the number of grams of hydrogen in the compound by calculating the number of grams of hydrogen in the given amount of H2O.
    • If the compound contains oxygen, calculate the number of grams of oxygen in it by subtracting the masses of carbon and hydrogen from the given total mass of compound.
    ? g O  =  (given) g total  -  (calculated) g C  -  (calculated) g H

    •  Calculate the empirical formula of the compound from the grams of carbon, hydrogen, and oxygen.
    Sample Question: Dianabol is one of the anabolic steroids that has been used by some athletes to increase the size and strength of their muscles.The molecular formula of Dianabol, which consists of carbon, hydrogen, and oxygen, can be determined using the data from two different experiments. In the first experiment, 14.765 g of Dianabol is burned, and 43.257 g CO2 and 12.395 g H2O are formed. In the second experiment, the molecular mass of Dianabol is found to be 300.44.  What is the molecular formula for Dianabol?

    ? g O  =  14.765 g total  - 11.805 g C  -  1.3870 g H  =  1.573 g O
    We now calculate the empirical formula.
    The empirical formula is C10H14O. We use it to calculate the molecular formula:
    Empirical formula mass  =  10(12.011)  +  14(1.00794)  +  1(15.9994)  =  150.22

    molecular formula         C20H28O2




     

    Ionization Energy

    Ionization Energy:

    Energy required to remove one mole of electrons from one mole of gaseous atoms

    Factors affecting Ionization Energy
    • Atomic size
      • As atomic size increases the ionization energy increases
    • Shielding affect
      • Ionization energy decreases as shielding affect increases

      Trend of ionization energy in the periodic table:

      • Ionization energy decreases down the group

        • As we move down the group shell size increases and so the distance from the nucleus increases hence ionization energy decreases
        • Also as we move down the group more electrons are being added, hence shielding affect increases.
      • Ionization energy increases across the period
        • As we move across the period the shielding affect remains constant
        • BUT across the period atomic size decreases due to INCREASE in EFFECTIVE NUCLEAR CHARGE which causes the ionization energy to increase

       The following videos will help you understand the trend :






      Ionisation Energy - Variation


      He > H
      One extra proton therefore the
      nuclear charge is greater and the
      extra electron has gone into the
      same energy level.  Increased
      attraction makes the electron
      harder to remove.

      Li < He
      Despite the increased nuclear
      charge, the outer electron is held
      less strongly because it is shielded
      by full inner level of electrons and is
      further away - easier to remove

      Be > Li
      Increased nuclear charge plus the
      electrons in the same energy level

      O < N
      Despite the increased nuclear charge the electron is easier to remove.  This is because,
      in N the three electrons in the 2p level are in separate orbitals whereas in O two of the
      four electrons are in the same orbital.  This leads to repulsion so less energy is needed
      for the removal of one of them.

      Na < Li
      Despite the increased nuclear charge due to the larger number of protons in the nucleus
      the increased shielding due to filled inner energy levels coupled with the greater distance
      from the nucleus means that the outer electron is held less strongly and easier to remove
      ATOMIC NUMBER

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